Equation 1 of problem 25

Expand the equation:

a)

\begin{align} ∑M_B=0 &\cssId{Step1}{=-F_A(d_1+d_2)+ \frac{1}{2} m·g·d_2=0}\\[3px] &\cssId{Step2}{+F_A·(d_1+d_2)+ \frac{1}{2}·m·g·d_2=0}\\[3px] &\cssId{Step3}{F_A =\frac{1/2·m · g ·d_2}{d_1+d_2}}\\[3px] &\cssId{Step4}{F_A= \frac{m · g ·d_2}{2·(d_1+d_2)}}\\[3px] &\cssId{Step5}{F_A= }\\[3px] \end{align}

1. Step 1: Form the equation of forces.
2. Step 2: Isolate to look for forces.
3. Step 3: Find strength relative to reference point A.